Solution Found!
A 6.0-cm-diameter gear rotates with angular velocity
Chapter 4, Problem 70P(choose chapter or problem)
A \(6.0\)-cm-diameter gear rotates with angular velocity \(\omega=\left(2.0+\frac{1}{2} t^{2}\right) \mathrm{rad} / \mathrm{s}\), where \(t\) is in seconds. At \(t=4.0 \mathrm{~s}\), what are:
a. The gear's angular acceleration?
b. The tangential acceleration of a tooth on the gear?
Equation Transcription:
Text Transcription:
6.0 cm
omega (2.0+1/2 t^2)rad/s
t
t=4.0 s
Questions & Answers
QUESTION:
A \(6.0\)-cm-diameter gear rotates with angular velocity \(\omega=\left(2.0+\frac{1}{2} t^{2}\right) \mathrm{rad} / \mathrm{s}\), where \(t\) is in seconds. At \(t=4.0 \mathrm{~s}\), what are:
a. The gear's angular acceleration?
b. The tangential acceleration of a tooth on the gear?
Equation Transcription:
Text Transcription:
6.0 cm
omega (2.0+1/2 t^2)rad/s
t
t=4.0 s
ANSWER:
Step 1 of 3
In this question, we need to find gear’s angular acceleration
In part b, we need to find tangential acceleration of tooth on the gear
Data given
Diameter of gear
Radius
Angular velocity