Solution Found!
A cyclist accelerates from rest at a rate of 1.00 m/s2.
Chapter 2, Problem 70GP(choose chapter or problem)
A cyclist accelerates from rest at a rate of \(1.00 \mathrm{~m} / \mathrm{s}^{2}\). How fast will a point on the rim of the tire (diameter ) at the top be moving after
? [Hint: At any moment, the lowest point on the tire is in contact with the ground and is at rest-see Fig.
Equation Transcription:
Text Transcription:
1.00 m/s2
Questions & Answers
QUESTION:
A cyclist accelerates from rest at a rate of \(1.00 \mathrm{~m} / \mathrm{s}^{2}\). How fast will a point on the rim of the tire (diameter ) at the top be moving after
? [Hint: At any moment, the lowest point on the tire is in contact with the ground and is at rest-see Fig.
Equation Transcription:
Text Transcription:
1.00 m/s2
ANSWER:Step 1 of 2
The radius of the wheel is calculated by;
Angular acceleration is calculated by;
