How does the magnitude of electrical force between a pair of charged particles change when the particles are moved half as far apart? One-third as far apart?

Solution 23E Step 1 of 3: Electric force From coulomb's law, the force between two charged particle is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. That is for two charge at r distance apart, K q q Electric force, F = r2 2 Where K is constant, q and q are two charges at r distance apart. 1 2 Which means The magnitude of the electric force is related to distance as, F r2 Step 2 of 3: To calculate force, when particles are moved half as far apart, By above dependency, 1 1 F 1 2 (2r) F 4 r2 F 4F Therefore, when the distance between the pair of charged particles is reduced to half, the electrical force between them increase four times.