Solution: In putting, the force with which a golfer strikes

QUESTION:

In putting, the force with which a golfer strikes a ball is planned so that the ball will stop within some small distance of the cup, say 1.0 m long or short, in case the putt is missed. Accomplishing this from an uphill lie (that is, putting the ball downhill, see Fig. 2–47) is more difficult than from a downhill lie. To see why, assume that on a particular green the ball decelerates constantly at \(1.8 \mathrm{\ m} / \mathrm{s}^{2}\) going downhill, and constantly at \(2.6\mathrm{\ m}/\mathrm{s}^2\) going uphill. Suppose we have an uphill lie 7.0 m from the cup. Calculate the allowable range of initial velocities we may impart to the ball so that it stops in the range 1.0 m short to 1.0 m long of the cup. Do the same for a downhill lie 7.0 m from the cup. What in your results suggests that the downhill putt is more difficult?

Equation Transcription:

Text Transcription:

1.8 m/s^2

2.6 m/s^2