A 0.25-kg skeet (clay target) is fired at an angle of 28°
Chapter 7, Problem 77GP(choose chapter or problem)
A skeet (clay target) is fired at an angle of \(28^{\circ}\) to the horizontal with a speed of \(25 \mathrm{\ m} / \mathrm{s}\) (Fig.
). When it reaches the maximum height,
, it is hit from below by a 15 -g pellet traveling vertically upward at a speed of \(230 \mathrm{\ m} / \mathrm{s}\). The pellet is embedded in the skeet. (a) How much higher, \(h^{\prime}\), does the skeet go up? (b) How much extra distance, \(\Delta x\), does the skeet travel because of the collision?
FIGURE 7-45 Problem 77.
Equation Transcription:
Text Transcription:
28^o
25 m/s
230 m/s
h'
x
28^o
v_0=25 m/s
v=230 m/s
h'
Delta x
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