(III) The americium nucleus NP by emitting an alpha
Chapter 26, Problem 44P(choose chapter or problem)
\(\text { (III) }\)The americium nucleus, \({ }_{95}^{241} \mathrm{Am}\), decays to a neptunium nucleus, \({ }_{93}^{237} \mathrm{~Np}\), by emitting an alpha particle of mass \(4.00260 u\) and kinetic energy \(5.5 \mathrm{MeV}\). Estimate the mass of the neptunium nucleus, ignoring its recoil, given that the americium mass is \(241.05682 u\).
Equation Transcription:
Text Transcription:
(III)
95 241Am
93 237Np
4.00260u
5.5MeV
241.05682u
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