Solved: An electron is accelerated from rest to speed v by
Chapter 26, Problem 62GP(choose chapter or problem)
An electron \(\left(m=9.11 \times 10^{-31} \mathrm{~kg}\right)\) is accelerated from rest to speed \(v\). by a conservative force. In this process, its potential energy decreases by
\(6.20 \times 10^{-14} j\). Determine the electron's speed, \(v\).
Equation Transcription:
Text Transcription:
(m=9.11 x 10-31kg)
v
6.20 x 10-14 J
v
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