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When Babe Ruth hit a homer over the 7.5-m-high right-field fence 95 m from home plate
Chapter 3, Problem 62GP(choose chapter or problem)
Problem 62GP
When Babe Ruth hit a homer over the 7.5-m-high right-field fence 95 m from home plate, roughly what was the minimum speed of the ball when it left the bat? Assume the ball was hit 1.0 m above the ground and its path initially made a 38° angle with the ground.
Questions & Answers
QUESTION:
Problem 62GP
When Babe Ruth hit a homer over the 7.5-m-high right-field fence 95 m from home plate, roughly what was the minimum speed of the ball when it left the bat? Assume the ball was hit 1.0 m above the ground and its path initially made a 38° angle with the ground.
ANSWER:
Solution 62GP
Step 1 of 3:
Baby Ruth hit the ball above a height yo and the ball reached a maximum horizontal distance Δx. The ball hit the fence 7.5 m above the ground. The launch angle of the ball with the horizontal is θ. We are going to find the initial speed of the ball vo. Consider the motion of the ball is the motion of a projectile.
The horizontal distance traveled by the ball Δx = 95 m
The initial height yo = 1.0 m
The final height y = 7.5 m
The launch angle θ = 38°
The acceleration due to gravity g = 9.8 m/s2