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Lunar Lander Descent: Initial and Final Velocities
Chapter 2, Problem 2.58(choose chapter or problem)
A lunar lander is descending toward the moon’s surface. Until the lander reaches the surface, its height above the surface of the moon is given by \(y(t)=b-c t+d t^{2}\), where \(b=800 \mathrm{~m}\) is the initial height of the lander above the surface, \(c=60.0 \mathrm{~m} / \mathrm{s}\), and \(d=1.05 \mathrm{~m} / \mathrm{s}^{2}\). (a) What is the initial velocity of the lander, at \(t=0\)? (b) What is the velocity of the lander just before it reaches the lunar surface?
Questions & Answers
QUESTION:
A lunar lander is descending toward the moon’s surface. Until the lander reaches the surface, its height above the surface of the moon is given by \(y(t)=b-c t+d t^{2}\), where \(b=800 \mathrm{~m}\) is the initial height of the lander above the surface, \(c=60.0 \mathrm{~m} / \mathrm{s}\), and \(d=1.05 \mathrm{~m} / \mathrm{s}^{2}\). (a) What is the initial velocity of the lander, at \(t=0\)? (b) What is the velocity of the lander just before it reaches the lunar surface?
ANSWER:
Step 1 of 2
Problem (a)
Given data
\(\begin{array}{l} y(t)=b-c t+d t^{2} \\ \mathrm{~b}=800 \mathrm{~m} \\ \mathrm{c}=60 \mathrm{~m} / \mathrm{s} \\ \mathrm{d}=1.05 \mathrm{~m} / \mathrm{s}^{2} \end{array}\)
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Lunar Lander Descent: Initial and Final Velocities
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Join us on an exciting lunar adventure as we explore the descent of a lunar lander towards the moon's surface. We'll unravel the physics behind its journey using the equation y(t) = b - ct + dt^2, and answer questions about the lander's initial and final velocities. Get ready to explore the dynamics of space exploration and lunar landings in this informative video!