Solution Found!
Dan gets on Interstate Highway 1-80 at Seward. Nebraska,
Chapter 2, Problem 63P(choose chapter or problem)
Dan gets on Interstate Highway I–80 at Seward, Nebraska, and drives due west in a straight line and at an average velocity of magnitude \(88 \mathrm{~km} / \mathrm{h} \text {. }\). After traveling \(76 \mathrm{~km}\), he reaches the Aurora exit (Fig. P2.63). Realizing he has gone too far, he turns around and drives due east \(34 \text { km }\) back to the York exit at an average velocity of magnitude \(72 \mathrm{~km} / \mathrm{h} \text {. }\). For his whole trip from Seward to the York exit, what are (a) his average speed and (b) the magnitude of his average velocity?
Equation Transcription:
Text Transcription:
88 km/h
76 km
34 km
72 km/h
Questions & Answers
QUESTION:
Dan gets on Interstate Highway I–80 at Seward, Nebraska, and drives due west in a straight line and at an average velocity of magnitude \(88 \mathrm{~km} / \mathrm{h} \text {. }\). After traveling \(76 \mathrm{~km}\), he reaches the Aurora exit (Fig. P2.63). Realizing he has gone too far, he turns around and drives due east \(34 \text { km }\) back to the York exit at an average velocity of magnitude \(72 \mathrm{~km} / \mathrm{h} \text {. }\). For his whole trip from Seward to the York exit, what are (a) his average speed and (b) the magnitude of his average velocity?
Equation Transcription:
Text Transcription:
88 km/h
76 km
34 km
72 km/h
ANSWER:
Solution 63P
a)To calculate the average speed, we have formula
=
The total distance travelled is 76 km+34 km=110 km
To find the time elapsed
=
=
To find the t for each leg of the journey
Seward to Auora,
t=