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Solved: Collision. The engineer of a passenger train
Chapter 2, Problem 70P(choose chapter or problem)
Collision. The engineer of a passenger train traveling at 25.0 m/s sights a freight train whose caboose is 200 m ahead on the same track (Fig. P2.70). The freight train is traveling at 15.0 m/s
in the same direction as the passenger train. The engineer of the passenger train immediately applies the brakes, causing a constant acceleration of \(0.100 \mathrm{~m} / \mathrm{s}^{2}\) in a direction opposite to the train’s velocity, while the freight train continues with constant speed. Take \(x=0\) at the location of the front of the passenger train when the engineer applies the brakes. (a) Will the cows nearby witness a collision? (b) If so, where will it take place? (c) On a single graph, sketch the positions of the front of the passenger train and the back of the freight train.
Equation Transcription:
Text Transcription:
0.100m/s^2
x=0
Questions & Answers
QUESTION:
Collision. The engineer of a passenger train traveling at 25.0 m/s sights a freight train whose caboose is 200 m ahead on the same track (Fig. P2.70). The freight train is traveling at 15.0 m/s
in the same direction as the passenger train. The engineer of the passenger train immediately applies the brakes, causing a constant acceleration of \(0.100 \mathrm{~m} / \mathrm{s}^{2}\) in a direction opposite to the train’s velocity, while the freight train continues with constant speed. Take \(x=0\) at the location of the front of the passenger train when the engineer applies the brakes. (a) Will the cows nearby witness a collision? (b) If so, where will it take place? (c) On a single graph, sketch the positions of the front of the passenger train and the back of the freight train.
Equation Transcription:
Text Transcription:
0.100m/s^2
x=0
ANSWER:
Solution 70P
Step 1:
The speed of the passenger train is 25 m/s.
The speed of the freight train is 15 m/s.
The distance between them was 200 meters.
The acceleration due to the brake of passenger train is,
.