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Solved: If a jumping frog can give itself the same initial
Chapter 3, Problem 8DQ(choose chapter or problem)
If a jumping frog can give itself the same initial speed regardless of the direction in which it jumps (forward or straight up), how is the maximum vertical height to which it can jump related to its maximum horizontal range \(R_{\max}=v_0^{\ 2}/g\)?
Questions & Answers
QUESTION:
If a jumping frog can give itself the same initial speed regardless of the direction in which it jumps (forward or straight up), how is the maximum vertical height to which it can jump related to its maximum horizontal range \(R_{\max}=v_0^{\ 2}/g\)?
ANSWER:Solution 8DQ
Step 1:
The equation for the maximum range of a projectile is, R = v02 sin 2𝜽 / g
Where, v0 - initial velocity with which the projectile is thrown
𝜽 - Angle it made with the x-axis
g - acceleration due to gravity
In the question, they have provided, Rmax = v02 /g
Comparing both equations, we can see that, sin 2𝜽 = 1
2𝜽 = sin-1 (1)
2𝜽 = 90°
𝜽 = 45°