Solution Found!
Answer: You apply a constant force to a 380-kg car as the
Chapter 6, Problem 12E(choose chapter or problem)
You apply a constant force \(\vec{F}=(-68.0 \mathrm{~N}) \hat{i}+(36.0 \mathrm{~N}) \hat{\jmath}\) to a \(380-\mathrm{kg}\) car as the car travels \(48.0 \mathrm{~m}\) in a direction that is 240.0^{\circ} counterclockwise from the +x-axis. How much work does the force you apply do on the car?
Equation Transcription:
°
Text Transcription:
\vec{F}=(-68.0 \{~N}) \hat{i}+(36.0 \{~N}) \hat\j}
380-kg
48.0 m
240.0^°
Questions & Answers
QUESTION:
You apply a constant force \(\vec{F}=(-68.0 \mathrm{~N}) \hat{i}+(36.0 \mathrm{~N}) \hat{\jmath}\) to a \(380-\mathrm{kg}\) car as the car travels \(48.0 \mathrm{~m}\) in a direction that is 240.0^{\circ} counterclockwise from the +x-axis. How much work does the force you apply do on the car?
Equation Transcription:
°
Text Transcription:
\vec{F}=(-68.0 \{~N}) \hat{i}+(36.0 \{~N}) \hat\j}
380-kg
48.0 m
240.0^°
ANSWER:
Solution 12E
Introduction
We will first write down the displacement in component form. Then we can easily calculate the dot product and find out the work done by the force.
Step 1
The angle in this problem with x axis is counterclockwise, that is the angle is positive with x axis.
Now the displacement is
And the angle is with x axis.