Solved: A woman bounces on a trampoline, going a little

Solution 8DQ

Step 1:

For the first bounce, she uses her muscular force upward and she will go up for a short distance, h.

Suppose, the mass of the woman as “m”. We know that the acceleration due to gravity is “g”.

The potential energy of the lady at a height “h” is, U = mgh

Consider. for the initial jump, the energy spent by the muscles as “M”

After the first jump, the energy acquired by the woman will be, Esecond jump = M + U

This is represented as Esecond jump because, this energy is used for the second jump.

So, the height of jump will increase and it will be h + Δh.

The potential energy acquired at maximum point will be, U ’ = mg ( h + Δh)

The energy acquired for the 3rd jump will be, E3rd = M + U’