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Solved: CALC A small block with mass 0.0400 kg is moving
Chapter 7, Problem 37E(choose chapter or problem)
Problem 37E
CALC A small block with mass 0.0400 kg is moving in the xy -plane. The net force on the block is described by the potential- energy function U(x , y) = (5.80 J/m2)x2 – (3.60 J/m3)y3. What are the magnitude and direction of the acceleration of the block when it is at the point (x = 0.300 m, y = 0.600 m)?
Questions & Answers
QUESTION:
Problem 37E
CALC A small block with mass 0.0400 kg is moving in the xy -plane. The net force on the block is described by the potential- energy function U(x , y) = (5.80 J/m2)x2 – (3.60 J/m3)y3. What are the magnitude and direction of the acceleration of the block when it is at the point (x = 0.300 m, y = 0.600 m)?
ANSWER:
Solution 37E
Step 1:
Mass of the block m = 0.04 Kg
Potential energy U(x,y) = (5.80 J/m2)x2 - (3.60 J/m3)y3 or
U = 5.8x2 - 3.6y3(simply)
x = 0.30m
y = 0.60m