Answer: Combining Conservation Laws. A 15.0-kg block is | StudySoup

Textbook Solutions for Sears and Zemansky's University Physics with Modern Physics

Chapter 8 Problem 44E

Question

Combining Conservation Laws. A \(15.0-\mathrm{kg}\) block is attached to a very light horizontal spring of force constant \(500.0 \mathrm{~N} / \mathrm{m}\) and is resting on a frictionless horizontal table. (Fig. E8.44). Suddenly it is struck by a \(\text { 3.00-kg }\) stone traveling horizontally at \(8.00 \mathrm{~m} / \mathrm{s}\) to the right, whereupon the stone rebounds at \(2.00 \mathrm{~m} / \mathrm{s}\)horizontally to the left. Find the maximum distance that the block will compress the spring after the collision.

Solution

Step 1 of 5

        Mass of stone  = 3.0 kg

        Mass of block  = 15.0kg

        Spring constant  = 500.0 N/m

        Initial velocity of stone  = 8.00 m/s

        Initial velocity of block  = 0 m/s

        After collision

        Stone rebounds with velocity  = -2.0m/s (opposite direction -x)

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Title Sears and Zemansky's University Physics with Modern Physics 13 
Author Hugh D. Young; Roger A. Freedman; A. Lewis Ford
ISBN 9780321696861

Answer: Combining Conservation Laws. A 15.0-kg block is

Chapter 8 textbook questions

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