Solved: Describe how you could use part (b) of Table 9.2

Chapter 9, Problem 13DQ

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QUESTION:

A turntable rotates with a constant \(2.25 \mathrm{rad} / \mathrm{s}^{2}\) angular acceleration. After \(4.00 \mathrm{~s}\) it has rotated through an angle of \(60.0 \mathrm{rad}\). What was the angular velocity of the wheel at the beginning of the \(\text { 4.00-s }\) interval?

Equation Transcription:

Text Transcription:

2.25 rad/s^2

4.00 s

60.0 rad

4.00-s

Questions & Answers

QUESTION:

A turntable rotates with a constant \(2.25 \mathrm{rad} / \mathrm{s}^{2}\) angular acceleration. After \(4.00 \mathrm{~s}\) it has rotated through an angle of \(60.0 \mathrm{rad}\). What was the angular velocity of the wheel at the beginning of the \(\text { 4.00-s }\) interval?

Equation Transcription:

Text Transcription:

2.25 rad/s^2

4.00 s

60.0 rad

4.00-s

ANSWER:

Solution 13DQ

Step 1:

Consider a slender rod of length L and mass M. The moment of inertia of the slender rod about an axis passing through one end,

I = ⅓ ML2

Consider two rods having lengths a and b are joined.

Moment of inertia of this system through its center of mass, Icm = 1/12 M (a2 + b2)

Where, M - Ma

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