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Answer: A Couple. Two forces equal in magnitude and
Chapter 11, Problem 21E(choose chapter or problem)
A Couple. Two forces equal in magnitude and opposite in direction, acting on an object at two different points, form what is called a couple. Two antiparallel forces with equal magnitudes
\(F_{1}=F_{2}=8.00 \mathrm{~N}\) are applied to a rod as shown in Fig. E11.21. (a) What should the distance l between the forces be if they are to provide a net torque of about the left end of the rod? (b) Is the sense of this torque clockwise or counterclockwise? (c) Repeat parts (a) and (b) for a pivot at the point on the rod where \(\overline{F_{2}}\) is applied.
Equation Transcription:
Text Transcription:
F_1=F_2=8.00 N
\overline F_2
Vec F_1
Vec F_2
3.00 m
Questions & Answers
QUESTION:
A Couple. Two forces equal in magnitude and opposite in direction, acting on an object at two different points, form what is called a couple. Two antiparallel forces with equal magnitudes
\(F_{1}=F_{2}=8.00 \mathrm{~N}\) are applied to a rod as shown in Fig. E11.21. (a) What should the distance l between the forces be if they are to provide a net torque of about the left end of the rod? (b) Is the sense of this torque clockwise or counterclockwise? (c) Repeat parts (a) and (b) for a pivot at the point on the rod where \(\overline{F_{2}}\) is applied.
Equation Transcription:
Text Transcription:
F_1=F_2=8.00 N
\overline F_2
Vec F_1
Vec F_2
3.00 m
ANSWER:
Solution 21E
Problem (a)
Step 1:
Anticlockwise force F1 = + 8.00 N
Clockwise force F2 = - 8.00 N
Net torque = 6.40 N
Distance from the origin to the point of application of F1 (d1 )= 3.0 m
Distance from the origin to the point of application of F2 (d2 )= 3.0 m + l