Answer: Sir Lancelot rides slowly out of the castle at

Chapter 11, Problem 46P

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QUESTION:

Sir Lancelot rides slowly out of the castle at Camelot and onto the \(\text { 12.0-m-long }\) drawbridge that passes over the moat (Fig. P11.46). Unbeknownst to him, his enemies have partially severed the vertical cable holding up the front end of the bridge so that it will break under a tension of \(5.80 \times 10^{3} \mathrm{~N}\). The bridge has mass \(200 \mathrm{~kg}\) and its center of gravity is at its center. Lancelot, his lance, his armor, and his horse together have a combined mass of \(600 \mathrm{~kg}\). Will the cable break before Lancelot reaches the end of the drawbridge? If so, how far from the castle end of the bridge will the center of gravity of the horse plus rider be when the cable breaks?

Equation Transcription:

 

Text Transcription:

12.0-m-long

5.80 x 10^3 N

200 kg

600 kg

Questions & Answers

QUESTION:

Sir Lancelot rides slowly out of the castle at Camelot and onto the \(\text { 12.0-m-long }\) drawbridge that passes over the moat (Fig. P11.46). Unbeknownst to him, his enemies have partially severed the vertical cable holding up the front end of the bridge so that it will break under a tension of \(5.80 \times 10^{3} \mathrm{~N}\). The bridge has mass \(200 \mathrm{~kg}\) and its center of gravity is at its center. Lancelot, his lance, his armor, and his horse together have a combined mass of \(600 \mathrm{~kg}\). Will the cable break before Lancelot reaches the end of the drawbridge? If so, how far from the castle end of the bridge will the center of gravity of the horse plus rider be when the cable breaks?

Equation Transcription:

 

Text Transcription:

12.0-m-long

5.80 x 10^3 N

200 kg

600 kg

ANSWER:

Solution 46P
Step 1:

        Length of the bridge = 12.0 m

        Mass of the bridge mB = 200 kg        (WB = mBg)

        Center of gravity of the bridge is at 6. 0 m

        Combined mass of Sir Lancelot, his armor, and his horse mL = 600 kg        (WL = mLg)

        Maximum tension can be applied T = 5.8 x 103 N

        Acceleration due to gravity g = 9.8 m/s2

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