A dockworker applies a constant horizontal force of 80.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.0 m in 5.00 s. (a) What is the mass of the block of ice? (b) If the worker stops pushing at the end of 5.00 s, how far does the block move in the next 5.00 s?

Solution 10 E Step 1: In this question, we need to find the mass of the ice block Distance covered in 5s when no force is applied Step 2: Let us consider the data given Horizontal force F = 80.0 N Distance covered x = 11 .0 m Time taken = t = 5 s Step 3: Let us find acceleration of the ice block This is obtained using x = ut + at 2 2 Here x displacement = 11.0 m u initial velocity = 0 a acceleration t = time taken = 5s Let us rearrange the equation to find acceleration 2(xut ) a = t Substituting the values we get a = 2(11.0 2 0 ×5s ) 5 s 22m a = 25 s 2 a = 0.88 m/s Hence we have obtained acceleration as 0.88 m/s 2