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Solved: Price of Chevy Cobalts The following data
Chapter 10, Problem 2RE(choose chapter or problem)
Problem 2RE
Problem
Price of Chevy Cobalts The following data represent the sales price in dollars for nine 2-year-old Chevrolet Cobalts in the Los Angeles area.
14050 |
13999 |
12999 |
10995 |
9980 |
8998 |
7889 |
7200 |
5500 |
|
Source: cars.com |
(a) Determine the sample mean and median price.
(b) Determine the range, sample standard deviation, and interquartile range.
(c) Redo (a) and (b) if the data value 14,050 was incorrectly entered as 41,050. How does this change affect the mean? The median? the range? the standard deviation? the interquartile range? Which of these values is resistant?
Questions & Answers
QUESTION:
Problem 2RE
Problem
Price of Chevy Cobalts The following data represent the sales price in dollars for nine 2-year-old Chevrolet Cobalts in the Los Angeles area.
14050 |
13999 |
12999 |
10995 |
9980 |
8998 |
7889 |
7200 |
5500 |
|
Source: cars.com |
(a) Determine the sample mean and median price.
(b) Determine the range, sample standard deviation, and interquartile range.
(c) Redo (a) and (b) if the data value 14,050 was incorrectly entered as 41,050. How does this change affect the mean? The median? the range? the standard deviation? the interquartile range? Which of these values is resistant?
ANSWER:
Answer:
Step 1 of 4
Price of Chevy Cobalts The following data represent the sales price in dollars for nine 2-year-old Chevrolet Cobalts in the Los Angeles area.
14050 |
13999 |
12999 |
10995 |
9980 |
8998 |
7889 |
7200 |
5500 |
|
(a)
Mean = = 10178.89
To find Median, we need to arrange the data in ascending order
5500 |
7200 |
7889 |
8998 |
9980 |
10995 |
12999 |
13999 |
14050 |
For odd series, median is the middlemost value of the ordered list.
Thus, by inspection we have Median M = 9980.