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Solved: Price of Chevy Cobalts The following data

Chapter 10, Problem 2RE

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QUESTION:

 Problem 2RE

 Problem

Price of Chevy Cobalts The following data represent the sales price in dollars for nine 2-year-old Chevrolet Cobalts in the Los Angeles area.

14050

13999

12999

10995

9980

8998

7889

7200

5500

 

Source: cars.com

(a) Determine the sample mean and median price.

(b) Determine the range, sample standard deviation, and interquartile range.

(c) Redo (a) and (b) if the data value 14,050 was incorrectly entered as 41,050. How does this change affect the mean? The median? the range? the standard deviation? the interquartile range? Which of these values is resistant?

Questions & Answers

QUESTION:

 Problem 2RE

 Problem

Price of Chevy Cobalts The following data represent the sales price in dollars for nine 2-year-old Chevrolet Cobalts in the Los Angeles area.

14050

13999

12999

10995

9980

8998

7889

7200

5500

 

Source: cars.com

(a) Determine the sample mean and median price.

(b) Determine the range, sample standard deviation, and interquartile range.

(c) Redo (a) and (b) if the data value 14,050 was incorrectly entered as 41,050. How does this change affect the mean? The median? the range? the standard deviation? the interquartile range? Which of these values is resistant?

ANSWER:

Answer:

Step 1 of 4

Price of Chevy Cobalts The following data represent the sales price in dollars for nine 2-year-old Chevrolet Cobalts in the Los Angeles area.

14050

13999

12999

10995

9980

8998

7889

7200

5500

 

(a)

      Mean = = 10178.89

     To find Median, we need to arrange the data in ascending order

   

5500

7200

7889

8998

9980

10995

12999

13999

14050

For odd series, median is the middlemost value of the ordered list.

Thus, by inspection we have Median M = 9980.

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