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Get Full Access to University Physics - 13 Edition - Chapter 4 - Problem 16e
Get Full Access to University Physics - 13 Edition - Chapter 4 - Problem 16e

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# An electron (mass = 9.11 X 10-31 kg) leaves one end of a ISBN: 9780321675460 31

## Solution for problem 16E Chapter 4

University Physics | 13th Edition

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Problem 16E

An electron (mass = 9.11 X 10-31 kg) leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is 1.80 cm away. It reaches the grid with a speed of 3.00 X 106 m/s. If the accelerating force is constant, compute (a) the acceleration; (b) the time to reach the grid; and (c) the net force, in newtons. Ignore the gravitational force on the electron.

Step-by-Step Solution:

Solution 16E Step 1 of 4: Given data, 31 Mass of electron, m= 9.11 × 10 kg Initial velocity, v =i Final velocity, v =3 × 10 m/s 6 f Distance, s= 1.8 cm 2 2 Using 1 cm =10 m s= 1.8× 10 m

Step 2 of 4

Step 3 of 4

##### ISBN: 9780321675460

This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 16E from chapter: 4 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: grid, Force, accelerating, speed, electron. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The answer to “An electron (mass = 9.11 X 10-31 kg) leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is 1.80 cm away. It reaches the grid with a speed of 3.00 X 106 m/s. If the accelerating force is constant, compute (a) the acceleration; (b) the time to reach the grid; and (c) the net force, in newtons. Ignore the gravitational force on the electron.” is broken down into a number of easy to follow steps, and 78 words. Since the solution to 16E from 4 chapter was answered, more than 1225 students have viewed the full step-by-step answer.

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