Solution Found!
Answer: A heat engine takes 0.350 mol of a diatomic ideal
Chapter 20, Problem 40P(choose chapter or problem)
A heat engine takes 0.350 mol of a diatomic ideal gas around the cycle shown in the pV-diagram of Fig. P20.40. Process \(1 \rightarrow 2\) is at constant volume, process \(2 \rightarrow 3\) is adiabatic, and \(3 \rightarrow 1\) is at a constant pressure of 1.00 atm. The value of \(\gamma\) for this gas is 1.40. (a) Find the pressure and volume at points 1, 2, and 3. (b) Calculate Q, W, and \(\Delta U\) for each of the three processes. (c) Find the net work done by the gas in the cycle. (d) Find the net heat flow into the engine in one cycle. (e) What is the thermal efficiency of the engine? How does this compare to the efficiency of a Carnot-cycle engine operating between the same minimum and maximum temperatures \(\mathrm{T}_{1}\) and \(\mathrm{T}_{2}\)?
Questions & Answers
QUESTION:
A heat engine takes 0.350 mol of a diatomic ideal gas around the cycle shown in the pV-diagram of Fig. P20.40. Process \(1 \rightarrow 2\) is at constant volume, process \(2 \rightarrow 3\) is adiabatic, and \(3 \rightarrow 1\) is at a constant pressure of 1.00 atm. The value of \(\gamma\) for this gas is 1.40. (a) Find the pressure and volume at points 1, 2, and 3. (b) Calculate Q, W, and \(\Delta U\) for each of the three processes. (c) Find the net work done by the gas in the cycle. (d) Find the net heat flow into the engine in one cycle. (e) What is the thermal efficiency of the engine? How does this compare to the efficiency of a Carnot-cycle engine operating between the same minimum and maximum temperatures \(\mathrm{T}_{1}\) and \(\mathrm{T}_{2}\)?
ANSWER:
Step 1 of 6
The sketch below shows a pV diagram of processes 1 to 2 at constant volume, process 2 to 3 is adiabatic, and 3 to 1 is at constant pressure.