Solution Found!
Figure E27.49 shows a portion of a silver ribbon with z1 =
Chapter 27, Problem 53E(choose chapter or problem)
Figure E27.53 shows a portion of a silver ribbon with \(z_{1}=11.8 \mathrm{~mm}) and \(y_{1}=0.23 \mathrm{~mm}\), carrying a current of 120 A in the \(+x\)-direction. The ribbon lies in a uniform magnetic field, in the \(y\)-direction, with magnitude 0.95 T. Apply the simplified model of the Hall effect presented in Section 27.9. If there are \(5.85 \times 10^{28}\) free electrons per cubic meter, find (a) the magnitude of the drift velocity of the electrons in the \(x\)-direction; (b) the magnitude and direction of the electric field in the \(z\)-direction due to the Hall effect; (c) the Hall emf.
Equation Transcription:
Text Transcription:
z_1=11.8 mm
y_1=0.23 mm
+x
y
5.85x10^28
x
z
y_1
z_1
Vector B
Questions & Answers
QUESTION:
Figure E27.53 shows a portion of a silver ribbon with \(z_{1}=11.8 \mathrm{~mm}) and \(y_{1}=0.23 \mathrm{~mm}\), carrying a current of 120 A in the \(+x\)-direction. The ribbon lies in a uniform magnetic field, in the \(y\)-direction, with magnitude 0.95 T. Apply the simplified model of the Hall effect presented in Section 27.9. If there are \(5.85 \times 10^{28}\) free electrons per cubic meter, find (a) the magnitude of the drift velocity of the electrons in the \(x\)-direction; (b) the magnitude and direction of the electric field in the \(z\)-direction due to the Hall effect; (c) the Hall emf.
Equation Transcription:
Text Transcription:
z_1=11.8 mm
y_1=0.23 mm
+x
y
5.85x10^28
x
z
y_1
z_1
Vector B
ANSWER:
Solution 53E
The expression for Hall effect is given by …..(1)
Where, n is the number of free electrons, q is the charge of an electron, is the electron current density,
is the magnetic field and
is the electric field.
We are required to calculate the magnitudes of drift velocity, electric field and Hall emf.
(a) The area of cross section of the ribbon .
Given, current
Concentration of free electrons
Charge of an electron
Therefore, the drift velocity