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A force of 800 N stretches a certain spring a distance of

Chapter 9, Problem 15E

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QUESTION:

A force of 800 N stretches a certain spring a distance of 0.200 m. (a) What is the potential energy of the spring when it is stretched 0.200 m? (b) What is its potential energy when it is compressed 5.00 cm?

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QUESTION:

A force of 800 N stretches a certain spring a distance of 0.200 m. (a) What is the potential energy of the spring when it is stretched 0.200 m? (b) What is its potential energy when it is compressed 5.00 cm?

ANSWER:

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The force constant of a spring can be calculated from the equation \(k=\frac{F}{x}\), where \(\mathrm{F}\) is the force applied on the spring and \(x\) is its elongation/compression.

The potential energy of a spring is given by \(P=\frac{1}{2} k x^{2}\).

 

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