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CALC A small block with mass 0.0400 kg is moving in the xy
Chapter 9, Problem 37E(choose chapter or problem)
CALC A small block with mass 0.0400 kg is moving in the xy -plane. The net force on the block is described by the potential- energy function U(x , y) = (5.80 J/m2)x2 – (3.60 J/m3)y3. What are the magnitude and direction of the acceleration of the block when it is at the point (x = 0.300 m, y = 0.600 m)?
Questions & Answers
QUESTION:
CALC A small block with mass 0.0400 kg is moving in the xy -plane. The net force on the block is described by the potential- energy function U(x , y) = (5.80 J/m2)x2 – (3.60 J/m3)y3. What are the magnitude and direction of the acceleration of the block when it is at the point (x = 0.300 m, y = 0.600 m)?
ANSWER:Solution 37E Step 1: Mass of the block m = 0.04 Kg 2 2 3 3 Potential energy U (x,y)(5.80 J/m )x - (3.60 J/m )y or U = 5.8x - 3.6y (simply) x = 0.30m y = 0.60m