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Physics / Sears and Zemansky's University Physics with Modern Physics 13 / Chapter 34 / Problem 90P

Sears and Zemansky's University Physics with Modern Physics | 13th Edition | ISBN: 9780321696861 | Authors: Hugh D. Young; Roger A. Freedman; A. Lewis Ford

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Chapter 34, Problem 90P

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QUESTION:

Problem 90P

The radii of curvature of the surfaces of a thin converging meniscus lens are R1 = +12.0 cm and R2 = +28.0 cm. The index of refraction is 1.60. (a) Compute the position and size of the image of an object in the form of an arrow 5.00 mm tall, perpendicular to the lens axis, 45.0 cm to the left of the lens. (b) A second converging lens with the same focal length is placed 3.15 m to the right of the first. Find the position and size of the final image. Is the final image erect or inverted with respect to the original object? (c) Repeat part (b) except with the second lens 45.0 cm to the right of the first.

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QUESTION:

Problem 90P

The radii of curvature of the surfaces of a thin converging meniscus lens are R1 = +12.0 cm and R2 = +28.0 cm. The index of refraction is 1.60. (a) Compute the position and size of the image of an object in the form of an arrow 5.00 mm tall, perpendicular to the lens axis, 45.0 cm to the left of the lens. (b) A second converging lens with the same focal length is placed 3.15 m to the right of the first. Find the position and size of the final image. Is the final image erect or inverted with respect to the original object? (c) Repeat part (b) except with the second lens 45.0 cm to the right of the first.

ANSWER:

Solution 90P

Step 1

(a)

Consider the lens maker formula to calculate the focal length of the lens.

Here, is the focal length, are the radius of curvature of the converging lens.

Substitute, 1.6 for , 12 cm for and 28 cm for .

For first lens object distance

Consider the lens formula to calculate the image distance for the first lens.

Here, is the image distance and is the object distance.

Substitute, for and for .

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