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Get Full Access to University Physics - 13 Edition - Chapter 9 - Problem 14e
Get Full Access to University Physics - 13 Edition - Chapter 9 - Problem 14e

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# A circular saw blade 0.200 m in diameter starts from rest.

ISBN: 9780321675460 31

## Solution for problem 14E Chapter 9

University Physics | 13th Edition

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University Physics | 13th Edition

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Problem 14E

A circular saw blade 0.200 m in diameter starts from rest. In 6.00 s it accelerates with constant angular acceleration to an angular velocity of 140 rad/s. Find the angular acceleration and the angle through which the blade has turned.

Step-by-Step Solution:

Solution 14E Introduction The initial and final angular velocity of the disk is given, and the time is given. We have to calculate the angular acceleration and the total angle covered by the disc. Step 1 The angular acceleration is given by Here we know that i 0 f 140 rad/s And t = 6.00 s. Hence the angular acceleration is 2 So the angular acceleration of the saw blade is 23.3 rad/s .

Step 2 of 2

##### ISBN: 9780321675460

The full step-by-step solution to problem: 14E from chapter: 9 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: angular, blade, acceleration, diameter, accelerates. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460. The answer to “A circular saw blade 0.200 m in diameter starts from rest. In 6.00 s it accelerates with constant angular acceleration to an angular velocity of 140 rad/s. Find the angular acceleration and the angle through which the blade has turned.” is broken down into a number of easy to follow steps, and 40 words. Since the solution to 14E from 9 chapter was answered, more than 374 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: University Physics, edition: 13.

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