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A uniform aluminum beam 9.00 m long, weighing 300 N, rests
Chapter 5, Problem 12E(choose chapter or problem)
A uniform aluminum beam 9.00 m long, weighing 300 N, rests symmetrically on two supports 5.00 m apart (?Fig. E11.12?). A boy weighing 600 N starts at point A and walks toward the right. (a) In the same diagram construct two graphs showing the upward forces FA and FB exerted on the beam at points A and B, as functions of the coordinate x of the boy. Let 1 cm = 100 N vertically, and 1 cm = 1.00 m horizontally. (b) From your diagram, how far beyond point B can the boy walk before the beam tips? (c) How far from the right end of the beam should support B be placed so that the boy can walk just to the end of the beam without causing it to tip?
Questions & Answers
QUESTION:
A uniform aluminum beam 9.00 m long, weighing 300 N, rests symmetrically on two supports 5.00 m apart (?Fig. E11.12?). A boy weighing 600 N starts at point A and walks toward the right. (a) In the same diagram construct two graphs showing the upward forces FA and FB exerted on the beam at points A and B, as functions of the coordinate x of the boy. Let 1 cm = 100 N vertically, and 1 cm = 1.00 m horizontally. (b) From your diagram, how far beyond point B can the boy walk before the beam tips? (c) How far from the right end of the beam should support B be placed so that the boy can walk just to the end of the beam without causing it to tip?
ANSWER:Solution 12 E Step 1: In the question,we need to construct a graph showing force F and F on the beam at A B point A and B From this graph we need find how far beyond the point B can the boy before the beam can tip In the third part we need to find the the distance at which the support B has to be placed such that the boy can walk tipping Data given Length of the beam L = 9.0 m Force exerted by the boy on the beam W =B600 N Weight of the beam W = L00 N Distance between the supports d = 5.0 m