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You push a piece of wood under the surface of a swimming

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 14DQ Chapter 12

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 14DQ

You push a piece of wood under the surface of a swimming pool. After it is completely submerged, you keep pushing it deeper and deeper. As you do this, what will happen to the buoyant force on it? Will the force keep increasing, stay the same, or decrease? Why?

Step-by-Step Solution:

Solution 14DQ Introduction We have to discuss what will happen to the buoyant force to a wooden block after it is submerged completely. Step 1 The force will stay same. The buoyant is equal to the weight of the water displaced by the object that is submerged into the water. Now after the wooden block is completely submerged into the water, the water displaced by the wooden block will not change and hence the buoyant force will not change and will remain same.

Step 2 of 1

Chapter 12, Problem 14DQ is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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You push a piece of wood under the surface of a swimming