A solid aluminum ingot weighs 89 N in air. (a) What is its volume? (b) The ingot is suspended from a rope and totally immersed in water. What is the tension in the rope (the apparent weight of the ingot in water)?
Solution 32E Step 1: Introduction : In this question, we need to find the volume for aluminium ingot In the second part, we need to find the tension of the rope that is used to suspend the ingot Data given Weight of ingot W = 89 N Step 2 : We can find the volume of aluminium ingot using V = m/ We have density of aluminium as = 2.7 × 10 kg /m 3 al Mass is given by m = W/g m = 89 N /9.8 m/s 2 m = 9.0 kg Hence we have volume as V = 9.0 kg/2.7 × 10 kg /m 3 3 3 V = 3.36 × 10 m 3 3 Hence the volume of ingot is 3.36 × 10 m
Textbook: University Physics
Author: Hugh D. Young, Roger A. Freedman
The answer to “A solid aluminum ingot weighs 89 N in air. (a) What is its volume? (b) The ingot is suspended from a rope and totally immersed in water. What is the tension in the rope (the apparent weight of the ingot in water)?” is broken down into a number of easy to follow steps, and 42 words. University Physics was written by and is associated to the ISBN: 9780321675460. This textbook survival guide was created for the textbook: University Physics, edition: 13. This full solution covers the following key subjects: ingot, Water, rope, solid, air. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The full step-by-step solution to problem: 32E from chapter: 12 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. Since the solution to 32E from 12 chapter was answered, more than 427 students have viewed the full step-by-step answer.