A solid aluminum ingot weighs 89 N in air. (a) What is its volume? (b) The ingot is suspended from a rope and totally immersed in water. What is the tension in the rope (the apparent weight of the ingot in water)?

Solution 32E Step 1: Introduction : In this question, we need to find the volume for aluminium ingot In the second part, we need to find the tension of the rope that is used to suspend the ingot Data given Weight of ingot W = 89 N Step 2 : We can find the volume of aluminium ingot using V = m/ We have density of aluminium as = 2.7 × 10 kg /m 3 al Mass is given by m = W/g m = 89 N /9.8 m/s 2 m = 9.0 kg Hence we have volume as V = 9.0 kg/2.7 × 10 kg /m 3 3 3 V = 3.36 × 10 m 3 3 Hence the volume of ingot is 3.36 × 10 m