Solution Found!
Answer: The article cited in Exercise 20 also gave the
Chapter 1, Problem 21E(choose chapter or problem)
The article cited in Exercise 20 also gave the following values of the variables y = number of culs-de-sac and z = number of intersections:
a. Construct a histogram for the y data. What proportion of these subdivisions had no culs-de-sac? At least one cul-de-sac?
b. Construct a histogram for the z data. What proportion of these subdivisions had at most five intersections? Fewer than five intersection
Questions & Answers
QUESTION:
The article cited in Exercise 20 also gave the following values of the variables y = number of culs-de-sac and z = number of intersections:
a. Construct a histogram for the y data. What proportion of these subdivisions had no culs-de-sac? At least one cul-de-sac?
b. Construct a histogram for the z data. What proportion of these subdivisions had at most five intersections? Fewer than five intersection
ANSWER:Answer :
Step 1 of 2 :
Given, The article cited in Exercise 20 also gave the following values of the variables y = number of culs-de-sac and z = number of intersections
Totally we have 47 observations
a)
The frequency of each dataset is
Y |
Frequency |
0 |
17 |
1 |
22 |
2 |
6 |
3 |
1 |
5 |
1 |
From Excel
> enter the data
> find the frequency
> select the data
> go to insert
> select the graph
From the above histogram the number of subdivisions having no-cul-de-sacs (that is y = 0) is 17/47 = 0.362 or 36.2%
The proportion having a least one cul-de-sacs (y1) is (47-17)/47 = 0.638 or 63.8%