Six hundred paving stones were examined for cracks, and 15

Step 1 of 3

Given the total number of stones is 600.

Then 600 stones are selected randomly.

562 is the total number of stones that were neither cracked nor discolored.

a).

Now we have to find the probability that it is cracked, discolored, or both.

Let A be the total stone is 600 and

Let B be the total stones that were neither cracked nor discolored is 562

P(cracked,discolored,or both) = P(A)-P(B)

P(cracked,discolored,or both) = 600 - 562

P(cracked,discolored,or both) = 38

Therefore the probability that it is cracked, discolored, or both is 38.

Now we have to find the probability that it is both cracked and discolored.

We know that A and B are the two events.

Let A be the total stone is 600 and

Let B be the total stones that were neither cracked nor discolored is 562

From the given information we have 15 cracked and 27 discolored.

Here P(A) is

\(\begin{array}{l} P(A)=\frac{15}{600} \\ P(A)=0.025 \\ P(B)=\frac{27}{600} \\ P(B)=0.045 \end{array}\)

and

The probability that it is cracked, discolored, or both is 38.

\(\begin{array}{l} P(A \cup B)=\frac{38}{600} \\ P(A \cup B)=0.0633 \end{array}\)