Three components are randomly sampled, one at a time, from

Chapter 2, Problem 12E

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QUESTION:

Three components are randomly sampled, one at a time, from a large lot. As each component is selected, it is tested. If it passes the test, a success (S) occurs; if it fails the test, a failure (F) occurs. Assume that  of the components in the lot will succeed in passing the test. Let  represent the number of successes among the three sampled components.

a. What are the possible values for

b. Find \(P(X=3)\).

c. The event that the first component fails and the next two succeed is denoted by FSS. Find  (FSS).

d. Find  and .

e. Use the results of parts (c) and (d) to find \(P(X=2)\).

f. Find \(P(X=1)\).

g. Find \(P(X=0)\).

h. Find \(\mu_{X}\).

i. Find \(\sigma_{X}^{2}\).

j. Let  represent the number of successes if four components are sampled. Find \(P(Y=3)\).

Equation Transcription:

Text Transcription:

P(X=3)

P(X=2)

P(X=1)

P(X=0)

mu_X

sigma_X^2

P(Y=3)

Questions & Answers

QUESTION:

Three components are randomly sampled, one at a time, from a large lot. As each component is selected, it is tested. If it passes the test, a success (S) occurs; if it fails the test, a failure (F) occurs. Assume that  of the components in the lot will succeed in passing the test. Let  represent the number of successes among the three sampled components.

a. What are the possible values for

b. Find \(P(X=3)\).

c. The event that the first component fails and the next two succeed is denoted by FSS. Find  (FSS).

d. Find  and .

e. Use the results of parts (c) and (d) to find \(P(X=2)\).

f. Find \(P(X=1)\).

g. Find \(P(X=0)\).

h. Find \(\mu_{X}\).

i. Find \(\sigma_{X}^{2}\).

j. Let  represent the number of successes if four components are sampled. Find \(P(Y=3)\).

Equation Transcription:

Text Transcription:

P(X=3)

P(X=2)

P(X=1)

P(X=0)

mu_X

sigma_X^2

P(Y=3)

ANSWER:

Solution

Step 1 of 10

Here we need to find the binomial distribution probabilities

Let x is the number of success

Here n=3,    p=0.8,     q=0.2

a) hereXB(n,p)

The pmf of binomial distribution is P(x)=; X=0,1,2,3

 The possible values of x is 0,1,2,3


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