Solution Found!
Solved: Prove that the lead l must be less than 2prms for
Chapter 8, Problem 8-73(choose chapter or problem)
QUESTION:
Prove that the lead l must be less than 2\(\pi\)r\(\mu_{\mathrm{s}}\) for the jack screw shown in Fig. 8–15 to be “self-locking.”
Questions & Answers
QUESTION:
Prove that the lead l must be less than 2\(\pi\)r\(\mu_{\mathrm{s}}\) for the jack screw shown in Fig. 8–15 to be “self-locking.”
ANSWER:Step 1 of 6
For the screw to be self-locking, it means that it is in equilibrium even if there is no force applied to its handle.To check this, we'll draw the free-body diagram of the screw.
Note that is angle which thread makes with the -axis, and the expression for it is: