Solution Found!
Answer: Locate the center of mass of the homogeneous rod
Chapter 9, Problem 9-1(choose chapter or problem)
QUESTION:
Locate the center of mass of the homogeneous rod bent into the shape of a circular arc.
Questions & Answers
QUESTION:
Locate the center of mass of the homogeneous rod bent into the shape of a circular arc.
Step 1 of 2
Given, the radius of the circular arc, R = 300 mm
Diagram:
Consider a small differential element of the rod, dL whose length is given by,
\(d L=R d \theta\)
The centroid of the differential element is located at
\(\tilde{x}=R \cos \theta\) and \(\bar{y}=R \sin \theta\)