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(a) Newtons method for approximating a root of an equation

Calculus | 8th Edition | ISBN: 9781285740621 | Authors: James Stewart ISBN: 9781285740621 127

Solution for problem 6 Chapter 14

Calculus | 8th Edition

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Calculus | 8th Edition | ISBN: 9781285740621 | Authors: James Stewart

Calculus | 8th Edition

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Problem 6

(a) Newtons method for approximating a root of an equation fsxd 0 (see Section 4.8) can be adapted to approximating a solution of a system of equations fsx, yd 0 and tsx, yd 0. The surfaces z fsx, yd and z tsx, yd intersect in a curve that intersects the xy-plane at the point sr, sd, which is the solution of the system. If an initial approximation sx1, y1d is close to this point, then the tangent planes to the surfaces at sx1, y1d intersect in a straight line that intersects the xy-plane in a point sx2, y2 d, which should be closer to sr, sd. (Compare with Figure 4.8.2.) Show that x2 x1 2 fty 2 fy t fx ty 2 fy tx and y2 y1 2 fx t 2 ftx fx ty 2 fy tx where f, t, and their partial derivatives are evaluated at sx1, y1d. If we continue this procedure, we obtain successive approximations sxn, yn d. (b) It was Thomas Simpson (17101761) who formulated Newtons method as we know it today and who extended it to functions of two variables as in part (a). (See the biography of Simpson on page 520.) The example that he gave to illustrate the method was to solve the system of equations xx 1 yy 1000 xy 1 yx 100 In other words, he found the points of intersection of the curves in the figure. Use the method of part (a) to find the coordinates of the points of intersection correct to six decimal places. 7et14ppx06 05/12/10 MasterID: 01651 FIGURE FOR PROBLEM 6 y 4 2 0 2 4 x

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Overview week of 9/12/16 3.3 Rules of Differentiation Power of X: d n (n­1) Power Rule: / Xdx= nX Quotient Rule: / f(x)/g(x) = [(f(x) * g(x)) – (f(x) * g(x))] / [g(x)] 2 dx Product Rule: / [dxx) * g(x)] = [f(x) * g’(x)] + [g(x) * f’(x)] Chain Rule: / [dxg(x))] = [f(g(x))]’ * g’(x) Constant Multiple: Power rule d /dx(cf(x)) = c * f ’(x) 3.4...

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Chapter 14, Problem 6 is Solved
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Textbook: Calculus
Edition: 8
Author: James Stewart
ISBN: 9781285740621

The full step-by-step solution to problem: 6 from chapter: 14 was answered by , our top Calculus solution expert on 11/10/17, 05:27PM. Since the solution to 6 from 14 chapter was answered, more than 230 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Calculus, edition: 8. This full solution covers the following key subjects: method, system, figure, point, Plane. This expansive textbook survival guide covers 16 chapters, and 250 solutions. Calculus was written by and is associated to the ISBN: 9781285740621. The answer to “(a) Newtons method for approximating a root of an equation fsxd 0 (see Section 4.8) can be adapted to approximating a solution of a system of equations fsx, yd 0 and tsx, yd 0. The surfaces z fsx, yd and z tsx, yd intersect in a curve that intersects the xy-plane at the point sr, sd, which is the solution of the system. If an initial approximation sx1, y1d is close to this point, then the tangent planes to the surfaces at sx1, y1d intersect in a straight line that intersects the xy-plane in a point sx2, y2 d, which should be closer to sr, sd. (Compare with Figure 4.8.2.) Show that x2 x1 2 fty 2 fy t fx ty 2 fy tx and y2 y1 2 fx t 2 ftx fx ty 2 fy tx where f, t, and their partial derivatives are evaluated at sx1, y1d. If we continue this procedure, we obtain successive approximations sxn, yn d. (b) It was Thomas Simpson (17101761) who formulated Newtons method as we know it today and who extended it to functions of two variables as in part (a). (See the biography of Simpson on page 520.) The example that he gave to illustrate the method was to solve the system of equations xx 1 yy 1000 xy 1 yx 100 In other words, he found the points of intersection of the curves in the figure. Use the method of part (a) to find the coordinates of the points of intersection correct to six decimal places. 7et14ppx06 05/12/10 MasterID: 01651 FIGURE FOR PROBLEM 6 y 4 2 0 2 4 x” is broken down into a number of easy to follow steps, and 271 words.

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