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The number of large cracks in a length of pavement along a
Chapter 4, Problem 2SE(choose chapter or problem)
The number of large cracks in a length of pavement along a certain street has a Poisson distribution with a mean of 1 crack per 100 m.
a. What is the probability that there will be exactly 8 cracks in a 500 m length of pavement?
b. What is the probability that there will be no cracks in a 100 m length of pavement?
c. Let T be the distance in meters between two successive cracks. What is the probability density function of T ?
d. What is the probability that the distance between two successive cracks will be more than 50 m?
Questions & Answers
QUESTION:
The number of large cracks in a length of pavement along a certain street has a Poisson distribution with a mean of 1 crack per 100 m.
a. What is the probability that there will be exactly 8 cracks in a 500 m length of pavement?
b. What is the probability that there will be no cracks in a 100 m length of pavement?
c. Let T be the distance in meters between two successive cracks. What is the probability density function of T ?
d. What is the probability that the distance between two successive cracks will be more than 50 m?
ANSWER:
Solution 2SE
Step1 of 5:
Let us consider a random variable X it presents the number of large cracks in a length of pavement along a certain street and it has poisson distribution with mean of 1 crack per 100 m.
Let X follows poisson distribution with parameters “ ”.
Then the probability mass function of poisson distribution is given by:
, x = 0,1,2,...,n.
Where,
= parameter
n = sample size
x = random variable
e = mathematical constant.
Here our goal is:
a).We need to find the probability that there will be exactly 8 cracks in a 500 m length of pavement.
b.We need to find the probability that there will be no cracks in a 100 m length of pavement.
c).We need to find the probability density function of 7, When T be the distance in meters between two successive cracks.
d).We need to find the probability that the distance between two successive cracks will be more than 50 m.
Step2 of 5:
a).
Here we have
X = 8 and
=
= 5
Now,
The probability that there will be exactly 8 cracks in a 500 m length of pavement is given by
Consider,