# Terminal Voltage Calculation for Battery with Resistors

Chapter 26, Problem 1

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QUESTION:

Calculate the terminal voltage for a battery with an internal resistance of $$0.900 \Omega$$ and an emf of $$6.00 V$$ when the battery is connected in series with (a) an $$81.0-\Omega$$ resistor, and(ib) an $$810-\Omega$$ resistor.

##### Terminal Voltage Calculation for Battery with Resistors

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Unlock the secrets of battery performance in this video! We calculate the terminal voltage for a battery with internal resistance, connected in series with resistors of different values. Explore the effects of resistance on voltage in electrical circuits.

QUESTION:

Calculate the terminal voltage for a battery with an internal resistance of $$0.900 \Omega$$ and an emf of $$6.00 V$$ when the battery is connected in series with (a) an $$81.0-\Omega$$ resistor, and(ib) an $$810-\Omega$$ resistor.

Step 1 of 2:

(a)

Given:

Internal resistance: $$r=0.9 \Omega$$

$$\text { Emf: }=6 \mathrm{~V}$$

Resistance: $$R=81 \Omega$$

Total Resistance: $$R_{t}=R+r=81+0.9=81.9 \Omega$$

Current Flowing through the circuit: $$I=\frac{6}{81.9}=0.073 \mathrm{~A}$$

Terminal Voltage

$$\begin{array}{l} V=-I r \\ V=6-0.073(0.9) \\ V=6-0.0657=5.93 \mathrm{~V} \end{array}$$

Hence the terminal voltage is $$5.93V$$