Mass M is distributed uniformly along a line of length 2L. A particle with mass m is at a point that is a distance a above the center of the line on its perpendicular bisector (point P in below Fig.). For the gravitational force that the line exerts on the particle, calculate the components perpendicular and parallel to the line. Does your result reduce to the correct expression as a becomes very large? Figure:

Problem 90CP Solution 90 CP Step 1: Introduction : In this question, we need to find the perpendicular and parallel lines of force We need to justify if the if the result expression becomes very large Considering the figure given Step 2 : Considering the parallel force acting At the point P , which is located above the center of the line, hence the left and the right parts cancel each other Hence the parallel force will be 0 That is F parallel0