(II) One liter of alcohol (1000 cm3) in a flexible container is carried to the bottom of the sea, where the pressure is 2.6 x 106 N/m2. What will be its volume there?
Step 1 of 3</p>
V0=1000cm3=1x10-3m3 (the initial volume of the flexible container)
P=2.6x106 N/m2 (the pressure at the bottom of the sea)
B=1x109N/m2 (the bulk modulus for alcohol)
ΔV=? (change in volume of the object under volume stress)
V=? (final volume of the gas at the bottom of the sea)
Step 2 of 3</p>
Since the pressure is P=F/A
The decrease in volume of the gas under pressure.
Textbook: Physics: Principles with Applications
Author: Douglas C. Giancoli
Since the solution to 42P from 9 chapter was answered, more than 1001 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 42P from chapter: 9 was answered by , our top Physics solution expert on 03/03/17, 03:53PM. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. The answer to “(II) One liter of alcohol (1000 cm3) in a flexible container is carried to the bottom of the sea, where the pressure is 2.6 x 106 N/m2. What will be its volume there?” is broken down into a number of easy to follow steps, and 33 words. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. This full solution covers the following key subjects: alcohol, bottom, carried, container, Flexible. This expansive textbook survival guide covers 35 chapters, and 3914 solutions.