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Get Full Access to University Physics - 13 Edition - Chapter 16 - Problem 50e
Get Full Access to University Physics - 13 Edition - Chapter 16 - Problem 50e

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# A railroad train is traveling at 30.0 m/s in still air. ISBN: 9780321675460 31

## Solution for problem 50E Chapter 16

University Physics | 13th Edition

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Problem 50E

A railroad train is traveling at 30.0 m/s in still air. The frequency of the note emitted by the train whistle is 262 Hz. What ? frequency is heard by a passenger on a train moving in the opposite direction to the first at 18.0 m/s and (a) approaching the first and (b) receding from the first?

Step-by-Step Solution:

Solution 50 E Step 1 : In this question we need to find the frequency of the sound heard by the passenger in opposite direction with speed 18 m/s When he is approaching to first When he is receding from the first Data given frequency at source f = 262 Hz Velocity of passenger v =p18.0 m/s Velocity of sound in air is v a 343 m/s Velocity of source v = 30 m/s s Hence we have the velocity of the passenger with respect source v = v + v = 30 m/s + 18 m/s s p v = 48 m/s

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##### ISBN: 9780321675460

This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “A railroad train is traveling at 30.0 m/s in still air. The frequency of the note emitted by the train whistle is 262 Hz. What ? frequency is heard by a passenger on a train moving in the opposite direction to the first at 18.0 m/s and (a) approaching the first and (b) receding from the first?” is broken down into a number of easy to follow steps, and 57 words. This full solution covers the following key subjects: train, frequency, opposite, emitted, air. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. Since the solution to 50E from 16 chapter was answered, more than 289 students have viewed the full step-by-step answer. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 50E from chapter: 16 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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