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A natural gas mixture having a molar analysis 60% CH4, 30%
Chapter 13, Problem 13.8(choose chapter or problem)
A natural gas mixture having a molar analysis 60% \(\mathrm{CH}_{4}\), 30% \(\mathrm{C}_{2} \mathrm{H}_{6}\), 10% \(\mathrm{N}_{2}\) is supplied to a furnace like the one shown in Fig. P13.8, where it burns completely with 20% excess air. Determine
(a) the balanced reaction equation.
(b) the air–fuel ratio, both on a molar and a mass basis.
Questions & Answers
QUESTION:
A natural gas mixture having a molar analysis 60% \(\mathrm{CH}_{4}\), 30% \(\mathrm{C}_{2} \mathrm{H}_{6}\), 10% \(\mathrm{N}_{2}\) is supplied to a furnace like the one shown in Fig. P13.8, where it burns completely with 20% excess air. Determine
(a) the balanced reaction equation.
(b) the air–fuel ratio, both on a molar and a mass basis.
ANSWER:
Step 1 of 4
Data:
Assumptions and approach:
To obtain the corresponding balance equation, we calculate the corresponding components. After that, the air fuel ratio based on the molar is calculated as the fraction of the number of moles of air and the number of moles of fuel. The air-fuel mass-based ratio is calculated as the product of the molar mass ratios of the given components and the air-fuel ratio.