For a linear, freely rotating polymer molecule, the total

Chapter 14, Problem 14.9

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For a linear, freely rotating polymer molecule, the total chain length L depends on the bond length between chain atoms d, the total number of bonds in the molecule N, and the angle between adjacent backbone chain atoms u, as follows: L = Ndsina u 2 b (14.11) Furthermore, the average end-to-end distancefor a series of polymer molecules r in Figure 14.6is equal tor = d2N (14.12) A linear polyethylene has a number-average molecularweight of 300,000 g/mol; compute averagevalues of L and r for this material.

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