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Get Full Access to University Physics - 13 Edition - Chapter 17 - Problem 116p
Get Full Access to University Physics - 13 Edition - Chapter 17 - Problem 116p

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# BIO Basal Metabolic Rate. The basal metabolic rate is the

ISBN: 9780321675460 31

## Solution for problem 116P Chapter 17

University Physics | 13th Edition

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Problem 116P

BIO Basal Metabolic Rate. The ?basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 75-kg (165-lb) person of height 1.83 m (6 ft) has a body surface area of approximately 2.0 m2. (a) What is the net amount of heat this person could radiate per second into a room at 18°C (about 65°F) if his skin’s surface temperature is 30°C? (At such temperatures, nearly all the heat is infrared radiation, for which the body’s emissivity is 1.0, regardless of the amount of pigment.) (b) Normally, 80% of the energy produced by metabolism goes into heat, while the rest goes into things like pumping blood and repairing cells. Also normally, a person at rest can get rid of this excess heat just through radiation. Use your answer to part (a) to find this person’s basal metabolic rate.

Step-by-Step Solution:

Solution 116P Step 1 The rate of heat radiation is given by dQ 4 4 dt = A(T 1 T 2 ) From the given problem we know that = 1.0 8 2 4 = 5.67 × 10 W/m K 2 A = 2.0 m T 1 30°C = 303 K T = 18°C = 291 K 2 dQ = (1.0)(5.67 × 108 W/m K )(2.0 m )[(303 K) (291 K) ] = 142.6 W dt So the person can radiate 142.6 J of heat per second.

Step 2 of 2