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Acetylene is hydrogenated to form ethane. The feed to the
Chapter 4, Problem 4.39(choose chapter or problem)
Acetylene is hydrogenated to form ethane. The feed to the reactor contains 1.50 mol H 2/mol CzHz (3) Calculate the stoichiometric reactant ratio (mol Hz react/mol C2Hz react) and the yield ratio (kmol CzH6 formed/kmol Hz react). (b) Determine the limiting reactant and calculate the percentage by which the other reactant is in excess. (c) Calculate the mass feed rate of hydrogen (kg/s) required to produce 4 X 106 metric tons of ethane per year, assuming that the reaction goes to completion and that the process operates for 24 hours a day, 300 days a year. (d) There is a definite drawback to running with one reactant in excess rather than feeding the reactants in stoichiometric proportion. What is it? [Hint: In the process of part (c), what does the reactor effluent consist of and what will probably have to be done before the product ethane can be sold or used?]
Questions & Answers
QUESTION:
Acetylene is hydrogenated to form ethane. The feed to the reactor contains 1.50 mol H 2/mol CzHz (3) Calculate the stoichiometric reactant ratio (mol Hz react/mol C2Hz react) and the yield ratio (kmol CzH6 formed/kmol Hz react). (b) Determine the limiting reactant and calculate the percentage by which the other reactant is in excess. (c) Calculate the mass feed rate of hydrogen (kg/s) required to produce 4 X 106 metric tons of ethane per year, assuming that the reaction goes to completion and that the process operates for 24 hours a day, 300 days a year. (d) There is a definite drawback to running with one reactant in excess rather than feeding the reactants in stoichiometric proportion. What is it? [Hint: In the process of part (c), what does the reactor effluent consist of and what will probably have to be done before the product ethane can be sold or used?]
ANSWER:Step 1 of 9
A limiting reactant in the reaction gets ‘exhausted wholly’ and ceases the reaction with no further formation of products. Comparison based on mole ratio helps to determine this reactant.