Solution Found!
Assume that CO, CO2, H2 , and CH4 are insoluble in liquid
Chapter 13, Problem 13.11(choose chapter or problem)
Assume that \(\mathrm{CO}\), \(\mathrm{CO}_2\), \(\mathrm{H}_2\), and \(\mathrm{CH}_4\) are insoluble in liquid water.
(a) Determine the dew-point temperature of the product gas from the reformer at 1.6 MPa.
(b) What is the composition of the gas stream after the reformer gas has been cooled and equilibrated at 1.6MPa and \(35^{\circ} \mathrm{C}\)? At what rate (kg/h) has water been removed from the stream?
(c) Suppose that one-third of the total water removal determined in part (b) occurs in each of the units (waste-heat recovery, air cooler, water cooler) preceding the makeup gas compressor. Estimate the temperatures of the gas and liquid streams leaving each condensate recovery drum in this part of the process. At what rate is heat removed (kJ/h) in the waste-heat recovery, air-cooler, and water-cooler units? Speculate on why heat removal is done in stages; in other words, why not use either air or cooling water alone to reduce the temperature?
Questions & Answers
QUESTION:
Assume that \(\mathrm{CO}\), \(\mathrm{CO}_2\), \(\mathrm{H}_2\), and \(\mathrm{CH}_4\) are insoluble in liquid water.
(a) Determine the dew-point temperature of the product gas from the reformer at 1.6 MPa.
(b) What is the composition of the gas stream after the reformer gas has been cooled and equilibrated at 1.6MPa and \(35^{\circ} \mathrm{C}\)? At what rate (kg/h) has water been removed from the stream?
(c) Suppose that one-third of the total water removal determined in part (b) occurs in each of the units (waste-heat recovery, air cooler, water cooler) preceding the makeup gas compressor. Estimate the temperatures of the gas and liquid streams leaving each condensate recovery drum in this part of the process. At what rate is heat removed (kJ/h) in the waste-heat recovery, air-cooler, and water-cooler units? Speculate on why heat removal is done in stages; in other words, why not use either air or cooling water alone to reduce the temperature?
ANSWER:Step 1 of 18
(a)
\(\begin{aligned}
\text { Pressure }(P) & =1.6 \mathrm{MPa} \\
& =15.79 \mathrm{~atm} \\
\text { Temperature }(\mathrm{T}) & =855^{\circ} \mathrm{C} \\
& =1128 \mathrm{~K}
\end{aligned}\)
Mole fraction:
\(y_{\mathrm{H}_{2} \mathrm{O}}=0.3413\)
\(\begin{array}{l}
p_{\mathrm{H}_{2} \mathrm{O}}=y_{\mathrm{H}_{2} \mathrm{O}} P \\
=(0.3413) \times 15.79 \\
=5.389 \mathrm{~atm}
\end{array}\)
\(\begin{aligned}
5.389 \mathrm{~atm} & =5.460 \mathrm{bar} \\
& =4095.64 \mathrm{~mm} \mathrm{Hg}
\end{aligned}\)