A breakdown diode has iD = 106 (1 + vD/7)2 for 7 V < vD <
Chapter 10, Problem P10.82(choose chapter or problem)
A breakdown diode has iD = 106 (1 + vD/7)2 for 7 V < vD < 0 where iD is in amperes. Plot iD versus vD for the ranges 10 mA iD 0 and 7 V
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