Prove that if you had a heat engine whose efficiency was

Chapter 4, Problem 16P

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QUESTION:

Prove that if you had a heat engine whose efficiency was better than the ideal value (4.5), you could hook it up to an ordinary Carnot refrigerator to make a refrigerator that requires no work input.

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QUESTION:

Prove that if you had a heat engine whose efficiency was better than the ideal value (4.5), you could hook it up to an ordinary Carnot refrigerator to make a refrigerator that requires no work input.

ANSWER:

 

Step 1 of 3

A heat engine has a maximum efficiency of:

\(e=1-\frac{T_{c}}{T_{h}}\)

where \(T_{h}\) is the temperature of the hot reservoir from which heat \(Q_{h}\) is extracted and \(T_{c}\) is the temperature of the cold reservoir to which heat \(Q_{c}=Q_{h}-W\) is expelled after work \(W\) is extracted. From the second law of thermodynamics, the heat and temperature ratios satisfy (at the optimum efficiency):

\(\begin{array}{c} \frac{Q_{c}}{Q_{h}}=\frac{T_{c}}{T_{h}} \\ Q_{c}=Q_{h} \frac{T_{c}}{T_{h}} \end{array}\)

Thus the work done by an optimal heat engine is:

\(\begin{array}{c} W=Q_{h}-Q_{c}=Q_{h}-Q_{h} \frac{T_{c}}{T_{h}} \\ W=Q_{h}\left(1-\frac{T_{c}}{T_{h}}\right) \end{array}\)

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