(a) Estimate (roughly) the total power radiated by your

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(a) The average area of the human body is \(A=1.9 \mathrm{~m}^{2}\), and the temperature of the body is \(37.5^{\circ} \mathrm{C}\), that is \(T=310.65 \mathrm{~K}\). The irradiated power is given by:

\(P=\operatorname{Ae} \sigma T^{4}\)

substitute with the givens to get (assume that the human body has an emissivity of l, note that \(\sigma=5.67 \times 10^{-8} \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}^{4}\) is the Stefan-Boltzmann constant):

\(\begin{array}{c} P=\left(1.9 \mathrm{~m}^{2}\right)(1)\left(5.67 \times 10^{-8} \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}^{4}\right)(310.65 \mathrm{~K})^{4} \\ \approx 1.0 \mathrm{~kW} \\ P=1.0 \mathrm{~kW} \end{array}\)
the power that the human body loses if he was naked.